SOLVED: Sketching the Graph of a Logarithmic Function, find the domain, x

Transcript

Let's take a look at the function and its graph f of X and see if it matches the log based four of X minus three. The first thing I'm going to do is look back at the parent function. If I have Y and Becks, what would that look like? The parent functions always have the X intercept at one. The graph shape is going to grow in this direction because we know that the vertical ascent toe is always going to be at X equals zero. Let's find at least one more point that tells us how steep or flat our graph is. Let's see if X is one when I know. Why is it going to be 0? The power is one. Let's make this a little bit easier on ourselves by saying, "Why is one what is X so for to the one power is what and that would be four?" There's a point I can plot if I have a Y value of 11231234. Mhm has a nice shape. If I have a shape like this, I can use transformations to see my new function and see what the new graph would look like. That is telling me I have a horizontal shift. Horizontal shifts will move in opposite directions of what is said. This tells me to shift my graph to the right three…